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How to find the smallest file in a directory in Python
Sometime while creating a program or writing a script in Python we need to find the largest file in a current directory. This is very simple task and can done by running a following script:
import os
files = os.listdir(".")
smallest_file_size = 10000
smallest_file = ""
for file in files:
if os.path.isfile(file):
size = os.path.getsize(file)
if size < smallest_file_size:
smallest_file_size = size
smallest_file = file
print("the smallest file in current directory has filename "+smallest_file+ " and size: "+str(smallest_file_size)+" bytes.")
What does that code?
First, we are making a list of files in a current directory using os module. In order to understand, what does further code, we have to check, what kind of object we get by running os.listdir() command.
How to find the largest file in a directory in Python
Sometime while creating a program or writing a script in Python we need to find the largest file in a current directory. This is very simple task and can done by running a following script:
import os
files = os.listdir(".")
largest_file_size = 0
largest_file = ""
for file in files:
if os.path.isfile(file):
size = os.path.getsize(file)
if size < largest_file_size:
largest_file_size = size
largest_file = file
print("largest file in current directory has filename "+largest_file+ " and size: "+str(largest_file_size)+" bytes.")
Output in my case:
dima@linux-zsrx:~/python> ls -l
total 24
-rw-r--r-- 1 dima users 2036 May 17 16:29 dics.py
-rw-r--r-- 1 dima users 405 May 18 03:40 largest_file_in_directory.py
-rw-r--r-- 1 dima users 109 May 17 17:06 levyi
-rw-r--r-- 1 dima users 680 May 17 19:00 levyi.py
-rw-r--r-- 1 dima users 125 May 17 19:33 test01.py
-rw-r--r-- 1 dima users 241 May 18 00:33 translitgeo.py
dima@linux-zsrx:~/python> python smallest_file_in_directory.py
the smallest file in current directory has filename levyi and size: 109 bytes.
What does that code?
First, we are making a list of files in a current directory using os module. In order to understand, what does further code, we have to check, what kind of object we get by running os.listdir() command.
Normally we have to check, if chosen item is directory or file, but we know, that directory link cannot be the biggest item, that's why we dont't have to check it.
How to count files in a current directory in Python?
In order to count files in current directory (where your python script is located), you can run following code:
import os
files = [f for f in os.listdir('.') if os.path.isfile(f)]
number_of_files = 0
for f in files:
number_of_files += 1
print(number_of_files)
In order to show, how many files located in currect directory, I've used linux command ls. And then I started python script to show, how it counts the number of files in directory.
In definition of "files" variable you can see several python commands, combined into one row: os.listdir() provides the list of files in location you provide (in our case: '.' as a current directory), then we have to be sure, that we count only files and not sub-directories. To do that we have to loop files object and count it.
This is output:
ls
dics.py files.py levyi levyi.py test01.py translitgeo.py
python files.py
6
Keep in mind, that files is a list. In case you don't know, which type is a variable you create, you can use type method and then check in official Python documentation, how to work with it. In our case we can check it very easy:
import os
files = [f for f in os.listdir('.') if os.path.isfile(f)]
print(type(files))
and get following output:
<type 'list'>
Print current directory path in Python
In order to print current directory path in Python (meaning, directory, where a python script is located), you have to import os module and then run a following script:
dir_path = os.path.dirname(os.path.realpath(__file__))
print(dir_path)
os.path.dirname is defining the current path, where your python script is stored and second line prints it into command line (terminal).
Output:
dima@linux-zsrx:~/python> python files.py
/home/dima/python
dima@linux-zsrx:~/python>
How to burn ISO on USB drive using BalenaEtcher (with screenshots)
There're a lot of reasons, why do you want burn iso on your USB drive. May be you want create bootable USB drive or just backup your data. Etcher is very simple in use and effective way, how to burn ISO image on USB drive in Linux.
In this case I'm using openSUSE Linux distro, but I'm sure, balenaEtcher works the same in other distros as well.
Let's run Etcher:
